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python-pycurl-7.19.0-12.fc18.armv6hl

Package Attributes
RPM  python-pycurl-7.19.0-12.fc18.armv6hl.rpm Architecture  armv6hl Size  229761 Created  2017/08/04 11:24:44 UTC
Package Specification
Summary A Python interface to libcurl
Group Development/Languages
License LGPLv2+ or MIT
Home Page http://pycurl.sourceforge.net/
Description

PycURL is a Python interface to libcurl. PycURL can be used to fetch objects identified by a URL from a Python program, similar to the urllib Python module. PycURL is mature, very fast, and supports a lot of features.

Requires
libpython2.7.so.1.0  
libcurl  
rpmlib(PayloadFilesHavePrefix)  
rpmlib(FileDigests)  
rpmlib(CompressedFileNames)  
libgcc_s.so.1  
libpthread.so.0  
rpmlib(PartialHardlinkSets)  
rpmlib(PayloadIsXz)  
libc.so.6  
libcurl.so.4  
Provides
pycurl
pycurl.so
python-pycurl
python-pycurl(armv6hl-32)

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