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You are here: Home / LBN / Up2date / Core Linux / BastionLinux 19 / python-pycurl-7.19.0-15.1.fc19.armv6hl

python-pycurl-7.19.0-15.1.fc19.armv6hl

Package Attributes

RPM python-pycurl-7.19.0-15.1.fc19.armv6hl.rpm

Architecture armv6hl

Size 233123

Created 2019/09/30 07:00:37 UTC

Package Specification

Summary	A Python interface to libcurl
Group	Development/Languages
License	LGPLv2+ or MIT
Home Page	http://pycurl.sourceforge.net/
Description	PycURL is a Python interface to libcurl. PycURL can be used to fetch objects identified by a URL from a Python program, similar to the urllib Python module. PycURL is mature, very fast, and supports a lot of features.
Requires	libpython2.7.so.1.0 rtld(GNU_HASH) libcurl python(abi) rpmlib(PayloadFilesHavePrefix) rpmlib(FileDigests) libgcc_s.so.1(GCC_3.5) rpmlib(CompressedFileNames) keyutils-libs libgcc_s.so.1 libpthread.so.0 rpmlib(PartialHardlinkSets) rpmlib(PayloadIsXz) libc.so.6 libcurl.so.4
Provides	pycurl pycurl.so python-pycurl python-pycurl(armv6hl-32)